1845 Mississippi gubernatorial election
Appearance
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County results Brown: 50–60% 60–70% 70–80% 80–90% 90–100% Coopwood: 50–60% 60–70% | |||||||||||||||||
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The 1845 Mississippi gubernatorial election was held on November 3, 1845, to elect the governor of Mississippi. Albert G. Brown, a Democrat won against Whig Thomas Coopwood and candidate Issac N. Davis.[1][2]
Results
[edit]Party | Candidate | Votes | % | |
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Democratic | Albert G. Brown | 28,310 | 66.1% | |
Whig | Thomas B. Coopwood | 12,852 | 30.0% | |
Issac N. Davis | 1,683 | 3.9% | ||
Total votes | 42,854 | 100.00 | ||
Democratic hold |
Elections in Mississippi |
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References
[edit]- ^ a b Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Westport, CT: Meckler Books. pp. 168–169.
- ^ Rowland, Dunbar (1925). History of Mississippi, the Heart of the South. Vol. 1. S. J. Clarke publishing Company.
- ^ Dublin, Michael J. (2011). United States Gubernatorial Elections, 1776-1860 : The Official Results by State and County. McFarland & Company, Incorporated Publishers. p. 132. ISBN 9780786453245.
- ^ "The Results for Governor" (fee required). The Mississippi Trader and Natchez Gazette. January 17, 1846. p. 2.