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1845 Mississippi gubernatorial election

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1845 Mississippi gubernatorial election
← 1843 November 3, 1845 1847 →
 
Nominee Albert G. Brown Thomas B. Coopwood
Party Democratic Whig
Popular vote 28,310 12,852
Percentage 66.1% 30.0%

County results
Brown:      50–60%      60–70%      70–80%      80–90%      90–100%
Coopwood:      50–60%      60–70%

Governor before election

Albert G. Brown
Democratic

Elected Governor

Albert G. Brown
Democratic

The 1845 Mississippi gubernatorial election was held on November 3, 1845, to elect the governor of Mississippi. Albert G. Brown, a Democrat won against Whig Thomas Coopwood and candidate Issac N. Davis.[1][2]

Results

[edit]
Mississippi gubernatorial election, 1845[1][3][4]
Party Candidate Votes %
Democratic Albert G. Brown 28,310 66.1%
Whig Thomas B. Coopwood 12,852 30.0%
Issac N. Davis 1,683 3.9%
Total votes 42,854 100.00
Democratic hold

References

[edit]
  1. ^ a b Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Westport, CT: Meckler Books. pp. 168–169.
  2. ^ Rowland, Dunbar (1925). History of Mississippi, the Heart of the South. Vol. 1. S. J. Clarke publishing Company.
  3. ^ Dublin, Michael J. (2011). United States Gubernatorial Elections, 1776-1860 : The Official Results by State and County. McFarland & Company, Incorporated Publishers. p. 132. ISBN 9780786453245.
  4. ^ "The Results for Governor" (fee required). The Mississippi Trader and Natchez Gazette. January 17, 1846. p. 2.