1848 Ohio gubernatorial election
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 Election results by county Ford: 50-60% 60-70% 70-80% Weller: 50-60% 60-70% 70-80% No Data/Vote: | |||||||||||||||||
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The 1848 Ohio gubernatorial election was held on 10 October 1848, in order to elect the Governor of Ohio. Whig nominee and former member of the Ohio Senate Seabury Ford narrowly defeated Democratic nominee and former member of the U.S. House of Representatives from Ohio's 2nd district John B. Weller.[1]
General election
[edit]On election day, 10 October 1848, Whig nominee Seabury Ford won the election by a margin of 311 votes against his opponent Democratic nominee John B. Weller, thereby retaining Whig control over the office of Governor. Ford was sworn in as the 20th Governor of Ohio on 22 January 1849.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Whig | Seabury Ford | 148,756 | 49.93% | |
| Democratic | John B. Weller | 148,445 | 49.82% | |
| Scattering | 742 | 0.25% | ||
| Total votes | 297,943 | 100.00% | ||
| Whig hold | ||||
References
[edit]- ^ "Seabury Ford". National Governors Association. Retrieved 10 May 2024.
- ^ "OH Governor". ourcampaigns.com. 16 February 2005. Retrieved 10 May 2024.
Categories:
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- 1848 United States gubernatorial elections
- 1848 in Ohio
- October 1848 events
- 1840s in Ohio
- 1840s Ohio elections
- 1848 elections
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- United States gubernatorial elections in the 1840s
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- 1840s elections
- 1840s elections in North America
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