1804 United States presidential election in Ohio

1804 United States presidential election in Ohio
1808 →
President before election; Thomas Jefferson; Democratic-Republican	Elected President ; Thomas Jefferson; Democratic-Republican

The 1804 United States presidential election in Ohio took place as part of the 1804 United States presidential election. Voters chose three representatives, or electors, to vote for president and vice president. It was the first time that Ohio took part in United States presidential election.

Results

1804 United States presidential election in Ohio^[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic-Republican	Thomas Jefferson (incumbent)	2,593	87.69%	3
	Federalist	Charles Cotesworth Pinckney	364	12.31%	0
Totals			2,957	100.0%	3

References

^ "A New Nation Votes". elections.lib.tufts.edu. Retrieved July 3, 2023.

This Ohio elections-related article is a stub. You can help Wikipedia by expanding it.

[1] "A New Nation Votes". elections.lib.tufts.edu. Retrieved July 3, 2023.

[1]

v t e State results of the 1804 U.S. presidential election
Candidates	Thomas Jefferson Charles Cotesworth Pinckney
General articles	Election timeline
Local results	Connecticut Delaware Georgia Kentucky Maryland Massachusetts New Hampshire New Jersey New York North Carolina Ohio Pennsylvania Rhode Island South Carolina Tennessee Vermont Virginia
Other 1804 elections	House Senate