1820 United States presidential election in Ohio
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| Elections in Ohio |
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The 1820 United States presidential election in Ohio took place between November 1 and December 6, 1820, as part of the 1820 United States presidential election. Voters chose 8 representatives, or electors to the Electoral College, who voted for President and Vice President.
Ohio re-elected incumbent Democratic-Republican Party President James Monroe by a large margin. Although Monroe ran unopposed, John Quincy Adams received a minority of the vote as an opposition candidate. This is the most recent time a party won every county in the state.
Results
[edit]| 1820 United States presidential election in Ohio[1] | |||||
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| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic-Republican | James Monroe (incumbent) | 7,164 | 76.38% | 8 | |
| Democratic-Republican | John Quincy Adams | 2,215 | 23.62% | 0 | |
See also
[edit]References
[edit]- ^ Ohio. Secretary of State. (1909). Ohio election statistics: the general election. Springfield, Ohio: The Springfield Publishing Company, State Printers. p. 3. OCLC 5470967. Retrieved April 20, 2019.
State and district results of the 1820 United States presidential election | ||
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