1998 United States Senate election in Iowa
(Redirected from United States Senate election in Iowa, 1998)
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| Elections in Iowa |
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The 1998 United States Senate election in Iowa was held November 3, 1998. Incumbent Republican United States Senator Chuck Grassley sought re-election to a fourth term in the United States Senate, running against former State Representative David Osterberg, who won the Democratic nomination unopposed. Grassley had not faced a competitive election since 1980; this year proved no different, and Grassley defeated Osterberg in a landslide.
Democratic primary
[edit]Candidates
[edit]- David Osterberg, former State Representative
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | David Osterberg | 86,064 | 99.45% | |
| Democratic | Write-ins | 476 | 0.55% | |
| Total votes | 86,540 | 100.00% | ||
Republican primary
[edit]Candidates
[edit]- Chuck Grassley, incumbent United States Senator
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Chuck Grassley (Incumbent) | 149,943 | 99.72% | |
| Republican | Write-ins | 419 | 0.28% | |
| Total votes | 150,362 | 100.00% | ||
General election
[edit]Results
[edit]| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | Chuck Grassley (Incumbent) | 648,480 | 68.41% | −1.20% | |
| Democratic | David Osterberg | 289,049 | 30.49% | +3.29% | |
| Natural Law | Susan Marcus | 7,561 | 0.80% | −0.47% | |
| Socialist Workers | Margaret Trowe | 2,542 | 0.27% | +0.16% | |
| Write-ins | 275 | 0.03% | |||
| Majority | 359,431 | 37.92% | −4.50% | ||
| Turnout | 947,907 | ||||
| Republican hold | Swing | ||||
See also
[edit]References
[edit]- ^ a b "Results" (PDF). sos.iowa.gov. 1998. Retrieved October 15, 2019.
- ^ "Election info" (PDF). clerk.house.gov. 1998. Retrieved October 15, 2019.