1891 Iowa gubernatorial election

1891 Iowa gubernatorial election
	County results ; Boies: 40-50% 50-60% 60-70% 70-80%; Wheeler: 40-50% 50-60% 60-70%; Westfall: 30-40%
Governor before election; Horace Boies; Democratic	Elected Governor ; Horace Boies; Democratic

The 1891 Iowa gubernatorial election was held on November 3, 1891. Incumbent Democrat Horace Boies defeated Republican nominee Hiram C. Wheeler with 49.40% of the vote.

General election

Candidates

Major party candidates

Horace Boies, Democratic
Hiram C. Wheeler, Republican

Other candidates

A. J. Westfall, People's
Isaac T. Gibson, Prohibition

Results

1891 Iowa gubernatorial election^[1]
Party		Candidate	Votes	%
	Democratic	Horace Boies (incumbent)	207,594	49.40%
	Republican	Hiram C. Wheeler	199,381	47.45%
	Populist	A. J. Westfall	12,303	2.93%
	Prohibition	Isaac T. Gibson	915	0.22%
Majority			8,213
Turnout
	Democratic hold		Swing

References

^ Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved August 9, 2020.

[1] Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved August 9, 2020.

[1]