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Americium(IV) fluoride

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(Redirected from Americium quadrifluoride)
Americium(IV) fluoride
Names
IUPAC name
Americium(IV) fluoride
Other names
Americium tetrafluoride
Identifiers
3D model (JSmol)
ChemSpider
  • InChI=1S/Am.4FH/h;4*1H/q+4;;;;/p-4
    Key: QFBBQHPDWGVACX-UHFFFAOYSA-J
  • [F-].[F-].[F-].[F-].[Am+4]
Properties
AmF4
Molar mass 319 g·mol−1
Appearance tan solid
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).

Americium(IV) fluoride is the inorganic compound with the formula AmF4. It is a tan solid. In terms of its structure, solid AmF4 features 8-coordinate Am centers interconnected by doubly bridging fluoride ligands.[1]

References

[edit]
  1. ^ Greenwood, Norman N.; Earnshaw, Alan (1997). Chemistry of the Elements (2nd ed.). Butterworth-Heinemann. ISBN 978-0-08-037941-8.