1988 Missouri Attorney General election
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| Elections in Missouri |
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The 1988 Missouri Attorney General election was held on 8 November 1988 in order to elect the attorney general of Missouri. Republican nominee and incumbent attorney general William L. Webster defeated Democratic nominee Michael A. Wolff.[1]
General election
[edit]On election day, 8 November 1988, Republican nominee William L. Webster won re-election by a margin of 428,129 votes against his opponent Democratic nominee Michael A. Wolff, thereby retaining Republican control over the office of attorney general. Webster was sworn in for his second term on 9 January 1989.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | William L. Webster (incumbent) | 1,224,346 | 60.59 | |
| Democratic | Michael A. Wolff | 796,217 | 39.41 | |
| Total votes | 2,020,563 | 100.00 | ||
| Republican hold | ||||
See also
[edit]References
[edit]- ^ "1988 Attorney General General Election Results - Missouri". uselectionatlas.org. 20 December 2012. Retrieved 27 October 2024.
- ^ "MO Attorney General". ourcampaigns.com. 12 February 2018. Retrieved 27 October 2024.
Categories:
- 1988 Missouri elections
- 1988 in Missouri
- Missouri Attorney General elections
- 1988 elections
- November 1988 events
- November 1988 events in North America
- November 1988 events in the United States
- 1988 elections in North America
- 1988 elections in the United States
- 1980s elections in the United States
- 1980s elections
- 1980s elections in North America
- 1980s Missouri elections
- 1980s in Missouri
- Government of Missouri