1968 Missouri Attorney General election
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The 1968 Missouri Attorney General election was held on 5 November 1968 in order to elect the attorney general of Missouri. Republican nominee John Danforth defeated Democratic nominee and incumbent attorney general Norman H. Anderson.[1]
General election
[edit]On election day, 5 November 1968, Republican nominee John Danforth won the election by a margin of 72,133 votes against his opponent Democratic nominee Norman H. Anderson, thereby gaining Republican control over the office of attorney general. Danforth was sworn in as the 37th attorney general of Missouri on 13 January 1969.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | John Danforth | 891,498 | 52.11 | |
| Democratic | Norman H. Anderson (incumbent) | 819,365 | 47.89 | |
| Total votes | 1,710,863 | 100.00 | ||
| Republican gain from Democratic | ||||
See also
[edit]References
[edit]- ^ "1968 Attorney General General Election Results - Missouri". uselectionatlas.org. 24 April 2007. Retrieved 27 October 2024.
- ^ "MO Attorney General". ourcampaigns.com. 11 February 2021. Retrieved 27 October 2024.
Categories:
- 1968 Missouri elections
- 1968 in Missouri
- Missouri Attorney General elections
- 1968 elections
- November 1968 events
- November 1968 events in North America
- November 1968 events in the United States
- 1968 elections in North America
- 1968 elections in the United States
- 1960s elections in the United States
- 1960s elections
- 1960s elections in North America
- 1960s Missouri elections
- 1960s in Missouri
- Government of Missouri