1824 Missouri gubernatorial election
Appearance
(Redirected from Missouri gubernatorial election, 1824)
| |||||||||||||||||
| |||||||||||||||||
County results Bates: 50-60% 60-70% 70-80% 80-90% 90-100% Ashley: 50–60% 70–80% 90–100% No Data/Vote: | |||||||||||||||||
|
Elections in Missouri |
---|
The 1824 Missouri gubernatorial election was held on August 2, 1824, Frederick Bates defeated Lt. Gov William Henry Ashley. Both candidates were members of the Democratic-Republican Party. The death of Frederick Bates in August 1825,[1] meant that the next election for governor of Missouri would be held little more than a year after this election.[2]
Results
[edit]Party | Candidate | Votes | % | ±% | |
---|---|---|---|---|---|
Democratic-Republican | Frederick Bates | 6,165 | 57.10 | ||
Democratic-Republican | William Henry Ashley | 4,631 | 42.90 | ||
Majority | 1,534 | 14.20 | −29.82 | ||
Turnout | 10,796 | ||||
Democratic-Republican hold | Swing |
References
[edit]- ^ "SOS, Missouri – State Archives: Governors". Sos.mo.gov. Retrieved March 18, 2013.
- ^ "MO Governor – Special Election Race – Dec 08, 1825". Our Campaigns. March 8, 2005. Retrieved March 18, 2013.
- ^ "MO Governor Race – Aug 02, 1824". Our Campaigns. March 8, 2005. Retrieved March 18, 2013.
Categories:
- 1824 United States gubernatorial elections
- Missouri gubernatorial elections
- 1824 Missouri elections
- August 1824 events
- United States gubernatorial elections in the 1820s
- 1824 in Missouri
- 1820s in Missouri
- 1820s Missouri elections
- 1824 elections
- 1824 elections in North America
- 1824 elections in the United States
- Government of Missouri