1840 United States presidential election in New Hampshire
(Redirected from United States presidential election in New Hampshire, 1840)
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| Elections in New Hampshire |
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The 1840 United States presidential election in New Hampshire took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.
New Hampshire voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New Hampshire by a margin of 10.78%.
Results
[edit]| 1840 United States presidential election in New Hampshire[1] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Martin Van Buren of New York | Richard M. Johnson of Kentucky | 32,774 | 54.66% | 7 | 100.00% | ||
| Whig | William Henry Harrison of Ohio | John Tyler of Virginia | 26,310 | 43.88% | 0 | 0.00% | ||
| Liberty | James G. Birney of New York | Thomas Earle of Pennsylvania | 872 | 1.45% | 0 | 0.00% | ||
| Total | 59,956 | 100.00% | 7 | 100.00% | ||||
See also
[edit]References
[edit]- ^ "1840 Presidential General Election Results – New Hampshire". U.S. Election Atlas. Retrieved December 23, 2013.
State and district results of the 1840 United States presidential election | ||
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