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1786 New Hampshire gubernatorial election

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1786 New Hampshire gubernatorial election

← 1785 14 March 1786 1787 →
 
Nominee John Sullivan John Langdon
Party Federalist Anti-Federalist
Popular vote 4,309 3,600
Percentage 50.30% 42.02%

President before election

John Langdon
Anti-Federalist

Elected President

John Sullivan
Federalist

The 1786 New Hampshire gubernatorial election was held on 14 March 1786 in order to elect the President of New Hampshire. (The office would be renamed to Governor in 1792.) Incumbent Anti-Federalist President John Langdon was defeated in his re-election bid by Federalist candidate John Sullivan, who had initially finished third during the previous President election.[1]

General election

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On election day, 14 March 1786, Federalist candidate John Sullivan won the election by a margin of 709 votes against incumbent Anti-Federalist President John Langdon, thereby gaining Federalist control over the office of President. Sullivan was sworn in as the 3rd President of New Hampshire on 6 June 1786.[2]

Results

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New Hampshire gubernatorial election, 1786
Party Candidate Votes %
Federalist John Sullivan 4,309 50.30
Anti-Federalist John Langdon (incumbent) 3,600 42.02
Scattering 658 7.68
Total votes 7,079 100.00
Federalist gain from Anti-Federalist

References

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  1. ^ "John Langdon". National Governors Association. Retrieved 24 January 2024.
  2. ^ "NH Governor". ourcampaigns.com. 1 June 2005. Retrieved 24 January 2024.