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1826 New Hampshire gubernatorial election

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1826 New Hampshire gubernatorial election

← 1825 14 March 1826 1827 →
 
Nominee David L. Morril Benjamin Pierce
Party Democratic-Republican Democratic-Republican
Popular vote 17,578 12,287
Percentage 58.08% 40.59%

County results
Morril:      50–60%      60–70%      70–80%
Pierce:      50–60%      60–70%

Governor before election

David L. Morril
Democratic-Republican

Elected Governor

David L. Morril
Democratic-Republican

The 1826 New Hampshire gubernatorial election was held on 14 March 1826 in order to elect the governor of New Hampshire. Incumbent Democratic-Republican governor David L. Morril defeated former Democratic-Republican member of the New Hampshire House of Representatives Benjamin Pierce.[1]

General election

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On election day, 14 March 1826, incumbent Democratic-Republican governor David L. Morril won re-election by a margin of 5,291 votes against his opponent Democratic-Republican candidate Benjamin Pierce, thereby retaining Democratic-Republican control over the office of governor. Morril was sworn in for his third term on 7 June 1826.[2]

Results

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New Hampshire gubernatorial election, 1826
Party Candidate Votes %
Democratic-Republican David L. Morril (incumbent) 17,578 58.08
Democratic-Republican Benjamin Pierce 12,287 40.59
Scattering 403 1.33
Total votes 30,268 100.00
Democratic-Republican hold

References

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  1. ^ "David L. Morril". National Governors Association. Retrieved 1 April 2024.
  2. ^ "NH Governor". ourcampaigns.com. 2 June 2005. Retrieved 1 April 2024.