1836 United States presidential election in New Hampshire
(Redirected from United States presidential election in New Hampshire, 1836)
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 County Results
Van Buren 50-60% 60-70% 70-80% 80-90%
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| Elections in New Hampshire |
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The 1836 United States presidential election in New Hampshire took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.
New Hampshire voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New Hampshire by a margin of 50.02%. As of 2020, this remains the strongest ever performance by any presidential candidate in New Hampshire since the creation of the modern Democratic party in 1828.
Results
[edit]| 1836 United States presidential election in New Hampshire[1] | ||||||||
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| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | Martin Van Buren of New York | Richard M. Johnson of Kentucky | 18,697 | 75.01% | 7 | 100.00% | ||
| Whig | William Henry Harrison of Ohio | Francis Granger of New York | 6,228 | 24.99% | 0 | 0.00% | ||
| Total | 24,925 | 100.00% | 7 | 100.00% | ||||
See also
[edit]References
[edit]- ^ "1836 Presidential General Election Results - New Hampshire". U.S. Election Atlas. Retrieved December 23, 2013.
State and district results of the 1836 United States presidential election | ||
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