1884 United States presidential election in Louisiana
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Parish Results
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Elections in Louisiana |
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Government |
The 1884 United States presidential election in Louisiana took place on November 4, 1884. All contemporary 38 states were part of the 1884 United States presidential election. State voters chose eight electors to the Electoral College, which selected the president and vice president.
Louisiana voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine by a margin of 14.85%.
Results
[edit]1884 United States presidential election in Louisiana[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Grover Cleveland of New York | Thomas Andrews Hendricks of Indiana | 62,594 | 57.22% | 8 | 100.00% | ||
Republican | James Gillespie Blaine of Maine | John Alexander Logan of Illinois | 46,347 | 42.37% | 0 | 0.00% | ||
Prohibition | John Pierce St. John of Kansas | William Daniel of Maryland | 338 | 0.31% | 0 | 0.00% | ||
Greenback | Benjamin Franklin Butler of Massachusetts | Absolom Madden West of Mississippi | 120 | 0.11% | 0 | 0.00% | ||
Total | 109,399 | 100.00% | 8 | 100.00% |
See also
[edit]References
[edit]- ^ "1884 Presidential General Election Results - Louisiana". U.S. Election Atlas. Retrieved November 25, 2020.