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1881 Buffalo mayoral election

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Buffalo mayoral election, 1881
← 1879 November 8, 1881 (1881-11-08) 1883 (special) →
 
Nominee Grover Cleveland Milton Beebe
Party Democratic Republican
Popular vote 15,120 11,528
Percentage 56.74% 43.26%

Mayor before election

Alexander Brush
Republican

Elected mayor

Grover Cleveland
Democratic

The Buffalo mayoral election of 1881 saw the election of former Erie County Sheriff Grover Cleveland, who defeated architect and alderman Milton Beebe by what was considered a broad margin.[1]

Cleveland would not serve out his entire term as mayor, as he would be subsequently elected Governor of New York the following year.

Results

[edit]
1881 Buffalo mayoral election[2]
Party Candidate Votes %
Democratic Grover Cleveland 15,120 56.74%
Republican Milton Beebe 11,528 43.26%

References

[edit]
  1. ^ Przepasniak, Ellen (January 2, 2019). "Jan. 2, 1882: Grover Cleveland begins brief term as mayor of Buffalo". Buffalo News. Retrieved October 11, 2019.
  2. ^ Nevins, Allan. Grover Cleveland: A Study in Courage (1932) page 83