1845 Georgia gubernatorial election
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Elections in Georgia |
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The 1845 Georgia gubernatorial election was held on October 6, 1845, to elect the governor of Georgia. The incumbent governor, George W. Crawford, was re-elected to a second term in office.[2]
General election
[edit]Candidates
[edit]Whig
[edit]- George W. Crawford, incumbent governor.[3]
Democratic
[edit]- Matthew Hall McAllister, former mayor of Savannah.
Results
[edit]Party | Candidate | Votes | % | ±% | |
---|---|---|---|---|---|
Whig | George W. Crawford | 41,514 | 51.08% | −1.12 | |
Democratic | Matthew Hall McAllister | 39,763 | 48.92% | +1.12 | |
Total votes | 81,277 | 100 |
Notes
[edit]References
[edit]- ^ a b Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776 1860: The Official Results By State And County. McFarland. pp. 37–38. ISBN 9780786414390.
- ^ "Our Campaigns - GA Governor Race - Oct 06, 1845". www.ourcampaigns.com. Retrieved July 20, 2021.
- ^ "George W. Crawford (1798-1872)". New Georgia Encyclopedia. Retrieved July 20, 2021.
Categories:
- Georgia (U.S. state) gubernatorial elections
- 1845 United States gubernatorial elections
- 1845 Georgia (U.S. state) elections
- October 1845 events
- 1845 in Georgia (U.S. state)
- 1840s in Georgia (U.S. state)
- 1840s Georgia (U.S. state) elections
- 1845 elections
- 1845 elections in North America
- 1845 elections in the United States
- United States gubernatorial elections in the 1840s
- Government of Georgia (U.S. state)