1826 New Jersey gubernatorial election
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The 1826 New Jersey gubernatorial election was held on 26 October 1826 in order to elect the governor of New Jersey. Incumbent Democratic-Republican governor Isaac Halstead Williamson was re-elected by the New Jersey General Assembly as he ran unopposed.[1]
General election
[edit]On election day, 26 October 1826, incumbent Democratic-Republican governor Isaac Halstead Williamson was re-elected by the New Jersey General Assembly as he ran unopposed, thereby retaining Democratic-Republican control over the office of governor. Williamson was sworn in for his tenth term that same day.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic-Republican | Isaac Halstead Williamson (incumbent) | 52 | 100.00% | |
| Total votes | 52 | 100.00% | ||
| Democratic-Republican hold | ||||
References
[edit]- ^ "Isaac Halstead Williamson". National Governors Association. Retrieved 22 September 2024.
- ^ "Williams-burnett to Williamson". politicalgraveyard.com. 8 March 2023. Retrieved 22 September 2024.
Categories:
- 1826 New Jersey elections
- 1826 in New Jersey
- New Jersey gubernatorial elections
- 1826 elections
- 1826 United States gubernatorial elections
- October 1826 events
- 1820s in New Jersey
- 1820s New Jersey elections
- 1826 elections in North America
- 1826 elections in the United States
- Single-candidate elections
- Indirect elections
- Government of New Jersey
- United States gubernatorial elections in the 1820s