1856 United States presidential election in New Jersey

Main article: 1856 United States presidential election

1856 United States presidential election in New Jersey

November 4, 1856

Nominee James Buchanan John C. Frémont Millard Fillmore Party Democratic Republican Know Nothing Home state Pennsylvania California New York Running mate John C. Breckinridge William L. Dayton Andrew J. Donelson Electoral vote 7 0 0 Popular vote 46,943 28,338 24,115 Percentage 47.23% 28.51% 24.26%

County Results Buchanan   40-50%   50-60%   60-70% Frémont   50-60% Fillmore   40-50%   50-60%

President before election Franklin Pierce Democratic Elected President James Buchanan Democratic

The 1856 United States presidential election in New Jersey took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.

New Jersey voted for the Democratic candidate, James Buchanan, over Republican candidate, John C. Frémont, and the Know Nothing candidate, Millard Fillmore. Buchanan won the state by a margin of 18.72 percentage points, and would be the last Democratic presidential candidate to carry Cumberland County until Franklin D. Roosevelt in 1936, and the last to carry Passaic County until Roosevelt in 1932.

Results

1856 United States presidential election in New Jersey
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	James Buchanan of Pennsylvania	John C. Breckinridge of Kentucky	46,943	47.23%	7	100.00%
	Republican	John C. Frémont of California	William L. Dayton of New Jersey	28,338	28.51%	0	0.00%
	Know Nothing	Millard Fillmore of New York	Andrew Jackson Donelson of Tennessee	24,115	24.26%	0	0.00%
Total				99,396	100.00%	7	100.00%

See also

• United States presidential elections in New Jersey