1824 United States presidential election in South Carolina
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| Elections in South Carolina |
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The 1824 United States presidential election in South Carolina took place in 1824 as part of the 1824 United States presidential election. The state legislature chose 11 representatives, or electors to the Electoral College, who voted for President and Vice President.
South Carolina cast 11 eleven electoral votes for Andrew Jackson. These electors were elected by the South Carolina General Assembly, the state legislature, rather than by popular vote.[1]
Opinion poll
[edit]While presidential electors were selected by the legislature, polls were occasionally held to gauge popular opinion. However, these polls had little impact on the outcome of the legislative election. The returns listed below are incomplete.[2]
| Source | Date(s) administered |
Sample size |
Andrew Jackson |
John Adams |
William Crawford |
Henry Clay |
John Calhoun |
Others |
|---|---|---|---|---|---|---|---|---|
| A New Nation Votes[3] | July 5, 1824 | 4,027 | 88.83% | 7.90% | 2.51% | 0.40% | 0.20% | 0.17% |
Results
[edit]| 1824 United States presidential election in South Carolina[4] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic-Republican | Andrew Jackson | 154 | 100% | 11 | |
| Totals | 154 | 100% | 11 | ||
References
[edit]- ^ "1824 Presidential General Election Results". U.S. Election Atlas. Retrieved April 13, 2013.
- ^ "A New Nation Votes". elections.lib.tufts.edu. Retrieved May 24, 2024.
- ^ A New Nation Votes
- ^ "A New Nation Votes". elections.lib.tufts.edu. Retrieved May 24, 2024.
State and district results of the 1824 United States presidential election | ||
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