1799 Rhode Island gubernatorial election
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 County results Fenner: 90–100% | ||||||||||||||
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The 1799 Rhode Island gubernatorial election was held on 3 April 1799 in order to elect the governor of Rhode Island. Incumbent Democratic-Republican governor Arthur Fenner won re-election as he ran unopposed. The exact number of votes cast in this election are unknown.[1]
General election
[edit]On election day, 3 April 1799, incumbent Democratic-Republican governor Arthur Fenner won re-election as he ran unopposed, thereby retaining Democratic-Republican control over the office of governor. Fenner was sworn in for his tenth term on 5 May 1799.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic-Republican | Arthur Fenner (incumbent) | 100.00 | ||
| Total votes | 100.00 | |||
| Democratic-Republican hold | ||||
References
[edit]- ^ "Arthur Fenner". National Governors Association. Retrieved 5 April 2024.
- ^ "RI Governor". ourcampaigns.com. 5 June 2005. Retrieved 5 April 2024.
Categories:
- Rhode Island gubernatorial elections
- 1799 United States gubernatorial elections
- 1799 in Rhode Island
- 1790s in Rhode Island
- 1790s Rhode Island elections
- 1799 elections
- 1799 elections in North America
- 1799 elections in the United States
- United States gubernatorial elections in the 1790s
- Government of Rhode Island
- Single-candidate elections