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1872 Rhode Island gubernatorial election

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1872 Rhode Island gubernatorial election
← 1871 April 3, 1872 1873 →
 
Nominee Seth Padelford Olney Arnold
Party Republican Democratic
Popular vote 9,463 8,308
Percentage 53.25% 46.75%

County results
Padelford:      50–60%      60–70%
Arnold:      50–60%
Tie:      50%

Governor before election

Seth Padelford
Republican

Elected Governor

Seth Padelford
Republican

The 1872 Rhode Island gubernatorial election took place on April 3, 1872, in order to elect the governor of Rhode Island.[1] Republican candidate and incumbent governor Seth Padelford won his fourth and final one-year term as governor[2] against Democratic candidate Olney Arnold.[3]

Candidates

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Election

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Statewide

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1872 Rhode Island gubernatorial election[1]
Party Candidate Votes %
Republican Seth Padelford 9,463 53.25
Democratic Olney Arnold 8,308 46.75
Total votes 17,771 100.00
Republican hold

References

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  1. ^ a b Dubin, Michael J. (2014). United States Gubernatorial Elections, 1861-1911 | The Official Results by State and County. McFarland. p. 6. ISBN 9780786456468.
  2. ^ a b "Seth Padelford". National Governors Association. 1 January 2019. Retrieved 27 March 2024.
  3. ^ "Rhode Island Election | The State all Right!". Newport Daily News. 4 April 1872. p. 2. Retrieved 30 March 2024.
  4. ^ Bayles, Richard M., ed. (1891). History of Providence County, Rhode Island, Volume II (PDF). New York, NY, USA: W. W. Preston & Co. pp. 102–104. Retrieved 30 March 2024.