1846 Rhode Island gubernatorial election
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 County results Diman: 50–60% 60–70% 70–80% Jackson: 50–60% | |||||||||||||||||
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| Elections in Rhode Island |
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The 1846 Rhode Island gubernatorial election was held on 1 April 1846 in order to elect the governor of Rhode Island. Law and Order nominee and incumbent lieutenant governor Byron Diman defeated incumbent Democratic governor Charles Jackson. However, as no candidate received a majority of the total votes cast as was required by Rhode Island law, the election was forwarded to the Rhode Island legislature, who chose Diman as governor.[1]
General election
[edit]On election day, 1 April 1846, Law and Order nominee Byron Diman won the election by a margin of 86 votes against his opponent incumbent Democratic governor Charles Jackson, thereby gaining Law and Order control over the office of governor. Diman was sworn in as the 19th governor of Rhode Island on 6 May 1846.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Law and Order | Byron Diman | 7,477 | 49.77 | |
| Democratic | Charles Jackson (incumbent) | 7,391 | 49.20 | |
| Scattering | 155 | 1.03 | ||
| Total votes | 15,023 | 100.00 | ||
| Law and Order gain from Democratic | ||||
References
[edit]- ^ "Charles Jackson". National Governors Association. Retrieved 5 April 2024.
- ^ "RI Governor". ourcampaigns.com. 6 June 2005. Retrieved 5 April 2024.
- Rhode Island gubernatorial elections
- 1846 United States gubernatorial elections
- April 1846 events
- 1846 in Rhode Island
- 1840s in Rhode Island
- 1840s Rhode Island elections
- 1846 elections in the United States
- 1846 elections
- 1846 elections in North America
- United States gubernatorial elections in the 1840s
- Government of Rhode Island