1868 United States presidential election in Pennsylvania
Appearance
(Redirected from United States presidential election in Pennsylvania, 1868)
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County Results
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Elections in Pennsylvania |
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Government |
The 1868 United States presidential election in Pennsylvania took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose 26 representatives, or electors to the Electoral College, who voted for president and vice president.
Pennsylvania voted for the Republican nominee, Ulysses S. Grant, over the Democratic nominee, Horatio Seymour. Grant won Pennsylvania by a margin of 4.4%.
Results
[edit]1868 United States presidential election in Pennsylvania[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Republican | Ulysses S. Grant | 342,280 | 52.20% | 26 | |
Democratic | Horatio Seymour | 313,382 | 47.80% | 0 | |
Totals | 655,662 | 100.0% | 26 |
See also
[edit]References
[edit]- ^ "1868 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved August 3, 2012.