1848 United States presidential election in Illinois
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(Redirected from United States presidential election in Illinois, 1848)
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County Results
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Elections in Illinois |
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The 1848 United States presidential election in Illinois took place on November 7, 1848, as part of the 1848 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.
Illinois narrowly voted for the Democratic candidate, Lewis Cass, over Whig candidate Zachary Taylor and Free Soil candidate Martin Van Buren. Cass won Illinois by a tight margin of 2.49%. This was the last time until 2000 that Illinois would back a losing Democrat in a presidential election and the last time until 2004 that they would back a Democrat that lost the popular vote.
Results
[edit]1848 United States presidential election in Illinois[1][2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Lewis Cass of Michigan | William O. Butler of Kentucky | 55,952 | 44.91% | 9 | 100.00% | ||
Whig | Zachary Taylor of Louisiana | Millard Fillmore of New York | 52,853 | 42.42% | 0 | 0.00% | ||
Free Soil | Martin Van Buren of New York | Charles F. Adams, Sr. of Massachusetts | 15,702 | 12.60% | 0 | 0.00% | ||
Clay Whig | Henry Clay of Kentucky | – | 89 | 0.07% | 0 | 0.00% | ||
Total | 124,596 | 100.00% | 9 | 100.00% |
See also
[edit]References
[edit]- ^ "1848 Presidential General Election Results - Illinois". U.S. Election Atlas. Retrieved December 27, 2013.
- ^ "1848 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved December 27, 2013.