1843 United States Senate election in Pennsylvania
(Redirected from United States Senate election in Pennsylvania, 1843)
| Elections in Pennsylvania |
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 Government |
The 1843 United States Senate election in Pennsylvania was held on January 10, 1843. Future President of the United States James Buchanan was re-elected by the Pennsylvania General Assembly to the United States Senate.[1]
Results
[edit]The Pennsylvania General Assembly, consisting of the House of Representatives and the Senate, convened on January 10, 1843, to elect a new Senator to fill the term beginning on March 4, 1843. Incumbent Democrat James Buchanan, who was elected in 1834 and re-elected in 1836, was a successful candidate for re-election to another term. The results of the vote of both houses combined are as follows:
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | James Buchanan (Inc.) | 74 | 56.06 | |
| Whig | John Banks | 54 | 40.91 | |
| Democratic | Richard Brodhead | 1 | 0.76 | |
| Unknown | John Gibons | 1 | 0.76 | |
| N/A | Not voting | 2 | 1.52 | |
| Totals | 132 | 100.00% | ||
See also
[edit]References
[edit]- ^ a b "U.S. Senate Election - 10 January 1843" (PDF). Wilkes University. Retrieved December 22, 2013.