Wikipedia:Reference desk/Archives/Mathematics/2016 November 21
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November 21
[edit]Can someone take a look at this page here and tell me how does it prove in this sketch that on the cycloid? It doesn't make much sence to me even for a non-rigorous proof. יהודה שמחה ולדמן (talk) 01:16, 21 November 2016 (UTC)
- "I don't understand" is not a question that a reference desk is suited to answer. The relevant discussion is on page 8 of that document. (You could have saved me, and anyone else trying to help, 2 minutes by pointing this out yourself.) What precisely don't you understand from that argument? --JBL (talk) 20:32, 22 November 2016 (UTC)
History of computer science discipline
[edit]Please answer on the Computing Reference Desk |
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The following discussion has been closed. Please do not modify it. |
Hi all,
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Meaning of "algebraically increased by an amount equal to"
[edit]What does this mean (PDF file):
- (a) When p is 101 325 Pa and t is one of the temperatures listed in the attached table then the magnitude of the density in kg.m^-3 is as stated in the table, which is derived from the following formula:
- d_t = 13 595.08 / {1 + (18 150.36 t + 0.702 09 t^2 + 2.865 5 × 10^-3 t^3 + 2.621 × 10^-6 t^4 ) × 10^-8 }
- where d_t is the density in kg.m^-3 , and t is the temperature in °C;
- (c) When p differs from 101 325 Pa the magnitude of the density in kg.m^-3 as stated in the attached table or derived therefrom in accordance with the above linear interpolation shall be algebraically increased by an amount equal to 5.47 × 10^-7 (p - 101 325);
Do you multiply d_t by "5.47 × 10^-7 (p - 101 325)", divide by it, or what? 166.186.168.191 (talk) 02:55, 21 November 2016 (UTC)
- I understand this to mean that you calculate d_t from the table (or directly from the formula if you wish) and then add (or subtract) a correction equal to 5.47 x 10^-7 kg/m^3 times the amount that the pressure is above (or below) 101,325 Pa. So for a pressure of 101,326 Pa you would add a correction of 5.47 x 10^-7 kg/m^3. For a pressure of 101,323 Pa you would subtract a correction of 10.94 x 10^-7 kg/m^3 etc. The correction appears to be a function of pressure only, and not of temperature. Gandalf61 (talk) 11:06, 21 November 2016 (UTC)