Talk:Low-dropout regulator

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Misc

I contributed an edit [1] but didn't realize I wasn't signed in at the time. Is there a way to "claim" this edit? JonathonReinhart (talk) 20:08, 14 February 2010 (UTC)[reply]

reference to person

there was odd refence to Rincón-Mora in the article without any connection to what was being quoted from him or his books/publications so I removed it and just mentioning here incase someone wants to go look up what exactly was referred. —Preceding unsigned comment added by 88.113.116.175 (talk) 18:23, 9 September 2009 (UTC)[reply]

isn't the 'bandgap' link in this page leading to a wrong Bandgap page ?

No...that's right --Lagrangian 19:27, 9 October 2007 (UTC)[reply]

Vendor Reference

I keep trying to add something but it keeps getting reverted. I would like to discuss this, because I do not believe it to be "spam" yet everyone who reverts it keeps marking it as such. I am opening this to the general community.

I firmly believe that mentioning the number 1 supplier worldwide with a link (I will be happy to provide a resource) is not spam. Voltage regulators are not merely theoretical objects, they exist and are sold on a daily basis. As such, a link to a suppliers webpage is relevant as a reference to what regulators are available at present. It also gives an idea of what parameters are important and what average parameter values might be (by looking at the datasheet). Spam is when a user tries to put something on a page as vandalism or advertisement. Wikipedia is an information source, and providing information about reality is not spam! I will not revert unless I get support, but I do believe that this is realistic.--Lagrangian 17:58, 8 October 2007 (UTC)[reply]

What would happen, if...

...if I'd put ground and plus revers - so that the V-in is not positive as expected but negative? How many Ohm is the typical resistance of a LDO about? —Preceding unsigned comment added by 217.83.13.227 (talk) 23:19, 10 September 2007 (UTC)[reply]

some LDOs are specified to protect against this sort of thing, some will let out the blue smoke, it all depends on the detail of the design. 193.195.77.146 16:09, 12 November 2007 (UTC)[reply]

Whoever drew the diagram of the LDO should either put an NMOS in for the pass device, or flip the PMOS around so it makes sense. toki (talk) 05:28, 1 July 2008 (UTC)[reply]

Schematic is incorrect, wrong transistor type is used —Preceding unsigned comment added by 78.61.102.116 (talk) 23:34, 31 January 2010 (UTC)[reply]

Regulation

The topology of a LDO doesn't depend on pnp or pmos devices. It's also possible to build one with a npn or nmos transistor if a charge pump is available. — Preceding unsigned comment added by 92.231.36.234 (talk) 09:45, 20 January 2013 (UTC)[reply]

Schematic

The schematic is wrong. It shows an source-follower topology, which is backwards of what an LDO is... http://www.analog.com/library/analogDialogue/archives/41-05/ldo.html

See schematic half-way down the page...

The basic idea is that both types of transistor are current output devices, regardless of whether you take the output from the drain or source. If you're using a feedback loop anyway...

Comments: Apart from this issue, the schematic IS wrong in that it needs an NMOS device (the way the error amp inputs are hooked up), and the device shown is a PMOS symbol. On an NMOS, the arrow goes OUT of the source, on a PMOS it goes into the source. The pass device can be a PMOS if you switch the error amp connections and the source is moved to the high voltage side (input voltage)

Don't know how to edit the image.

AnnoE-9 (talk) 01:16, 8 July 2016 (UTC)[reply]

This is not even schematics of SPX1580. I do not imply to use schematics of SPX1580 but of a more simple circuit such as Microchip MCP1700. Bglazar (talk) 13:04, 14 July 2016 (UTC)[reply]

Common description

I suggest moving Efficiency and heat dissipation, Quiescent current and at least some parts of Specifications to Linear regulator as it is not specific to low-dropout linear regulator. Bglazar (talk) 10:55, 13 July 2016 (UTC)[reply]

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