Korasahalu
Korasahalu is an island in Guadalcanal Province, Solomon Islands.[1][2]
Geography
[edit]The highest point of the island is 65 meters. The island is located 3 km south of Cape Lauvi and 21 km west of Cape Henslow of Guadalcanal Island. To the north there are two more islets with a maximum height of 15 m. The island is separated from Guadalcanal by a deep strait. There is a lagoon within the island.
Population
[edit]There is no permanent population there, but the island is often visited by fishermen from neighboring islands.
References
[edit]- ^ Motteler, Lee S.; Bryan, Edwin Horace (1986). Pacific Island Names: A Map and Name Guide to the New Pacific. Bishop Museum Press. p. 49. ISBN 9780930897123. Retrieved 21 February 2019.
- ^ Pacific Islands Pilot: Western Groups (9 ed.). Hydrographer of the Navy. 1970. p. 355. ISBN 9780902539419. Retrieved 21 February 2019.
09°48′16″S 160°50′36″E / 9.80444°S 160.84333°E
| Central | |
|---|---|
| Choiseul | |
| Guadalcanal | |
| Isabel | |
| Makira-Ulawa | |
| Malaita | |
| Rennell and Bellona | |
| Temotu | |
| Western | |
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