1868 Belgian general election
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(Redirected from Belgian general election, 1868)
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63 of the 122 seats in the Chamber of Representatives 62 seats needed for a majority | ||||||||||||||||||||||||||||||||||
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Belgium portal |
General elections were held in Belgium on 9 June 1868.[1][2] In the elections for the Chamber of Representatives the result was a victory for the Liberal Party, which won 72 of the 122 seats.[2] Voter turnout was 55.6%, although only 55,297 people were eligible to vote.
Under the alternating system, elections were only held in five out of the nine provinces: Antwerp, Brabant, Luxembourg, Namur and West Flanders. A special election was held in the arrondissement of Tongeren.
Results
[edit]Chamber of Representatives
[edit]Party | Votes | % | Seats | |||||
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Won | Total | +/– | ||||||
Catholics | 16,918 | 55.07 | 33 | 50 | –2 | |||
Liberal Party | 13,619 | 44.33 | 30 | 72 | +2 | |||
Others | 184 | 0.60 | 0 | 0 | New | |||
Total | 30,721 | 100.00 | 63 | 122 | 0 | |||
Total votes | 30,721 | – | ||||||
Registered voters/turnout | 55,297 | 55.56 | ||||||
Source: Mackie & Rose,[3] Sternberger et al. |