1872 Belgian general election
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63 of the 124 seats in the Chamber of Representatives 63 seats needed for a majority | ||||||||||||||||||||||||||||||||||
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Belgium portal |
Partial general elections were held in Belgium on Tuesday 11 June 1872.[1][2] In the elections for the Chamber of Representatives the result was a victory for the Catholic Party, which won 71 of the 124 seats.[2] Voter turnout was 55.5%, although only 54,933 people were eligible to vote.
Under the alternating system, elections were only held in five out of the nine provinces: Antwerp, Brabant, Luxembourg, Namur and West Flanders.
The incumbent government was a Catholic government led by Jules Malou.
Results
[edit]Chamber of Representatives
[edit]Party | Votes | % | Seats | |||||
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Won | Total | +/– | ||||||
Catholic Party | 20,949 | 68.75 | 43 | 71 | –1 | |||
Liberal Party | 9,455 | 31.03 | 20 | 53 | +1 | |||
Others | 66 | 0.22 | 0 | 0 | New | |||
Total | 30,470 | 100.00 | 63 | 124 | 0 | |||
Total votes | 30,470 | – | ||||||
Registered voters/turnout | 54,933 | 55.47 | ||||||
Source: Mackie & Rose,[3] Sternberger et al. |
The results exclude the voting figures for the Nivelles constituency.[3]