1918 Connecticut Attorney General election
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The 1918 Connecticut Attorney General election was held on 5 November 1918 in order to elect the Attorney General of Connecticut. Republican nominee and incumbent member of the Connecticut House of Representatives Frank E. Healy defeated Democratic nominee Harrison Hewitt.[1]
General election
[edit]On election day, 5 November 1918, Republican nominee Frank E. Healy won the election by a margin of 6,949 votes against his opponent Democratic nominee Harrison Hewitt, thereby retaining Republican control over the office of Attorney General. Healy was sworn in as the 6th Attorney General of Connecticut in 1919.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Frank E. Healy | 83,953 | 52.16% | |
| Democratic | Harrison Hewitt | 77,004 | 47.84% | |
| Total votes | 160,957 | 100.00% | ||
| Republican hold | ||||
References
[edit]- ^ "Harrison Hewitt (D)". electionhistory.ct.gov. Retrieved 20 October 2024.
- ^ "1918 Nov 5 :: General Election :: Attorney General :: State of Connecticut". electionhistory.ct.gov. Retrieved 20 October 2024.
Categories:
- 1918 Connecticut elections
- 1918 in Connecticut
- Connecticut Attorney General elections
- November 1918 events in the United States
- 1918 elections in the United States
- 1910s Connecticut elections
- 1910s elections
- 1910s elections in North America
- 1910s elections in the United States
- 1910s in Connecticut
- Government of Connecticut