1918 Brunswick state election
The 1918 Brunswick state election was held on 22 December 1918 to elect the 60 members of the Landtag of the Free State of Brunswick.[1]
Results
[edit]| Party | Votes | % | Seats | |
|---|---|---|---|---|
| Social Democratic Party of Germany | 58,759 | 27.67 | 17 | |
| Brunswick State Electoral Association | 55,621 | 26.19 | 16 | |
| Independent Social Democratic Party of Germany | 51,672 | 24.33 | 14 | |
| German Democratic Party | 46,293 | 21.80 | 13 | |
| Total | 212,345 | 100.00 | 60 | |
| Valid votes | 212,345 | 99.92 | ||
| Invalid/blank votes | 177 | 0.08 | ||
| Total votes | 212,522 | 100.00 | ||
| Registered voters/turnout | 283,501 | 74.96 | ||
| Source: Elections in the Weimar Republic,[1] Elections in Germany[2] | ||||
References
[edit]- ^ a b Gonschior, Andreas. "Der Freistaat Braunschweig Landtagswahl 1918". Wahlen in der Weimarer Republik. Archived from the original on 2001-05-25. Retrieved 21 April 2022.
- ^ Schröder, Valentin. "Landtagswahlen Freistaat Braunschweig". Wahlen in der Deutschland. Retrieved 21 April 2022.
| Lower Saxony | |
|---|---|
| Brunswick | |
| Oldenburg | |
| Schaumburg-Lippe | |
| Local elections | |
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