1845 Virginia gubernatorial election
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The 1845 Virginia gubernatorial election was held on 17 December 1845 in order to elect the Governor of Virginia. Democratic nominee and former member of the U.S. House of Representatives from Virginia's 13th district William Smith won the election in the Virginia General Assembly as he ran unopposed.
General election
[edit]On election day, 17 December 1845, Democratic nominee William Smith easily won the election as he ran unopposed. Smith was sworn in as the 30th Governor of Virginia on 1 January 1846.[1]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | William Smith | 1 | 100.00 | |
| Total votes | 1 | 100.00 | ||
| Democratic hold | ||||
References
[edit]- ^ "VA Governor". ourcampaigns.com. June 10, 2008. Retrieved May 12, 2023.
- ^ Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson: McFarland & Company. ISBN 9780786414390.
Categories:
- 1845 Virginia elections
- Virginia gubernatorial elections
- 1845 United States gubernatorial elections
- December 1845 events
- 1845 in Virginia
- Indirect elections
- Single-candidate elections
- Government of Virginia
- 1840s in Virginia
- 1840s Virginia elections
- 1845 elections
- 1845 elections in North America
- 1845 elections in the United States
- United States gubernatorial elections in the 1840s