1809 Virginia gubernatorial election
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The 1809 Virginia gubernatorial election was held on 30 November 1809 in order to elect the Governor of Virginia. Incumbent Democratic-Republican Governor of Virginia John Tyler Sr. won re-election in the Virginia General Assembly as he ran unopposed.[1]
General election
[edit]On election day, 30 November 1809, Democratic-Republican nominee John Tyler Sr. easily won re-election as he ran unopposed. Tyler was sworn in for his second term on 1 December 1809.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic-Republican | John Tyler Sr. (incumbent) | 1 | 100.00 | |
| Total votes | 1 | 100.00 | ||
| Democratic-Republican hold | ||||
References
[edit]- ^ John Tyler at the Biographical Directory of Federal Judges, a publication of the Federal Judicial Center.
- ^ "VA Governor". ourcampaigns.com. February 10, 2013. Retrieved May 18, 2023.
- ^ Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson: McFarland & Company. ISBN 9780786414390.
Categories:
- 1809 Virginia elections
- Virginia gubernatorial elections
- 1809 United States gubernatorial elections
- November 1809 events
- Family of John Tyler
- 1809 in Virginia
- Indirect elections
- Single-candidate elections
- Government of Virginia
- 1800s in Virginia
- 1800s Virginia elections
- 1809 elections
- 1809 elections in North America
- 1809 elections in the United States
- United States gubernatorial elections in the 1800s