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November 11

Four consecutive years with two Friday the 13ths each

The years 2017, 2018, 2019, and 2020 are four consecutive years with two Friday the 13ths each (Jan 13 and Oct 13, Apr 13 and Jul 13, Sep 13 and Dec 13, and Mar 13 and Nov 13 respectively). Is it true that any four consecutive years with two Friday the 13ths each in either the Julian calendar or the Gregorian calendar must end with a leap year starting on Wednesday (or equivalently, with one exception in each 400-year period, consist of the next four consecutive years following a leap year starting on Friday)? If so, then it follows that the table below is complete.

Instances between 2000 and 2400
Jan 13, Oct 13	Apr 13, Jul 13	Sep 13, Dec 13	Mar 13, Nov 13
2017	2018	2019	2020
2045	2046	2047	2048
2073	2074	2075	2076
2113	2114	2115	2116
2141	2142	2143	2144
2169	2170	2171	2172
2209	2210	2211	2212
2237	2238	2239	2240
2265	2266	2267	2268
2293	2294	2295	2296
2305	2306	2307	2308
2333	2334	2335	2336
2361	2362	2363	2364
2389	2390	2391	2392

The exception is the year 2196. Adding 4 years to 2196 gives the non-leap century 2200, which has a Friday the 13th in June. Hence, the years 2197, 2198, 2199, and 2200 are not included in the above table. GeoffreyT2000 (talk) 06:39, 11 November 2019 (UTC)[reply]

I think that you are probably right. Bubba73 ^{You talkin' to me?} 16:03, 11 November 2019 (UTC)[reply]