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January 14

What is the value for n=4?

ƒ(n)=2^n(n-1)^n(n+2)

Do you mean

ƒ(n)=2^{n(n-1)ⁿ⁽ⁿ⁺²⁾}

or

ƒ(n)=2ⁿ(n-1)ⁿ(n+2)

or something else ? In any case, we won't do your homework for you, but just plug in 4 for every n, and solve. We will check your work, if you put it here. StuRat (talk) 02:49, 14 January 2014 (UTC)[reply]

A quick thought on primes!

All primes can be described,

P_β×[(P_α+P_α)×β]^β −P_α = [(P_α+P_α)×β]^{(P_α+P_α)×β} −P_α

where P_α = 1, and β = {1,2,3,4,5}. For example,

32×(2⁵)−1 = 2¹⁰−1

→ 1023 = 1023

Which is correct. But, is this generalization always true? Can Primes always be factored in this way? — Preceding unsigned comment added by 99.182.38.146 (talk) 05:07, 14 January 2014 (UTC)[reply]

Don't take this the wrong way, but you're clearly making your ideas overcomplicated, that's no good. Explain yourself, use common notation, define your terms. If P_alpha is 1, just put 1, etc. As it stands now, to be honest, I have no idea what you're asking, I can cancel stuff out and get an idea, but it just seems like random symbols for the sake of symbols. If you would care to explain your thought process, I'd be happy to work on this with you and see what we can figure out, though. Again, not to offend, but from experience, even with no idea what you're trying to say, given what you are asking and how you presented it, I'd say the answer is no.Phoenixia1177 (talk) 06:41, 14 January 2014 (UTC)[reply]

All of the questions this editor is asking are nonsense. I have removed the two above this one. Looie496 (talk) 08:44, 14 January 2014 (UTC)[reply]