Wikipedia:Reference desk/Archives/Mathematics/2013 September 7
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September 7
[edit]3D Protractor
[edit]Hello. Is there such thing as a 3D protractor, an instrument that can help one build a physical molecular model? Thanks in advance. --Mayfare (talk) 16:26, 7 September 2013 (UTC)
- Positioning goniometer may possibly help. Duoduoduo (talk) 16:53, 7 September 2013 (UTC)
- Precise angular positioning is done in Stereotactic surgery. Here is an example of such a three-dimensional protractor. But such devices are not common and tend to be expensive. --Mark viking (talk) 20:05, 7 September 2013 (UTC)
What are you do if I give $ 1 Millon ?
[edit]close request for opinion per talk desk consensus |
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The following discussion has been closed. Please do not modify it. |
What are you do if I give $ 1 Millon ? — Preceding unsigned comment added by 37.238.8.188 (talk) 19:43, 7 September 2013 (UTC)
There's nothing wrong with stimulating people, but prizes are for children, not grown-ups. Have either Newton, Euler, or Gauss ever won any "medals" or money for their countless results, proofs, and conjectures ? If any of them would've won such a sum for each of their ground-breaking discoveries, global economy would've been plummeted to the ground... :-) — 79.113.209.204 (talk) 19:32, 10 September 2013 (UTC)
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2D shell theorem?
[edit]Shell theorem says it applies to spherically symmetric objects. If I limit it to two dimensions does it apply to radially symmetric objects? (I can't write the problem in a form I can find the integral for.) RJFJR (talk) 21:29, 7 September 2013 (UTC)
- There is a version of the shell theorem that holds in any dimension, but with the appropriate Newtonian potential. In three dimensions, this is a 1/r law (for the potential) or equivalently a 1/r2 law (for the force). In two dimensions, on the other hand, it's a log(r) law (for the potential) or equivalently a 1/r law (for the force). (In n≠2 dimensions, the potential is for some constant C depending only on the dimension.) You can get from the three dimensional to the two dimensional result by dimensional reduction (extend a two dimensional body to an infinite cylinder in three dimensions by adding a z axis). Hope this helps, Sławomir Biały (talk) 00:16, 8 September 2013 (UTC)
- Thank you very much. RJFJR (talk) 01:44, 8 September 2013 (UTC)
- Not ? — Preceding unsigned comment added by 109.144.249.84 (talk) 00:12, 9 September 2013 (UTC)
- Yes, I meant . Sławomir Biały (talk) 00:30, 9 September 2013 (UTC)
I'd say it applies to any disc as long as the other object in question is also in the plane of the disk. Integrating shouldn't be that hard.--Jasper Deng (talk) 00:27, 9 September 2013 (UTC)
- Not with the usual gravitational field, no it doesn't. (It's true with a 1/r force law rather than a 1/r2 force law). To see that it doesn't work with the usual gravitational field, take a thin plate of unit mass density concentrated in the plate (of radius R, written in polar coordinates). The (standard) gravitational field exerted by this plate on a unit mass concentrated at the origin has y-coordinate zero and x-coordinate given by
- which diverges. Sławomir Biały (talk) 01:03, 9 September 2013 (UTC)