User talk:Tantalite

Welcome!

Hello, and welcome to Wikipedia. Thank you for your contributions.

Currently, you are editing without a username. You can continue to do so, as you are not required to log in to Wikipedia to read and edit articles; however, logging in will result in a username being shown instead of your IP address (yours is Tantalite). Logging in does not require any personal details, and there are many other benefits for logging in.

When you edit pages:

Please respect others' copyrights; do not copy and paste the contents from webpages directly.
Please use a neutral point of view when editing articles; this is possibly the most important Wikipedia policy.
If you are testing, please use the Sandbox to do so.
Do not add unreasonable contents into any articles, such as copyrighted text, advertisement messages, and text that is not related to an article's subject. Adding such content or editing articles maliciously is considered vandalism.

The Wikipedia Tutorial is a good place to start learning about Wikipedia. For now, if you are stuck, you can click the edit this page tab above, type {{helpme}} in the edit box, and then click Save Page; an experienced Wikipedian will be around shortly to answer any questions you may have. Also feel free to ask a question on my talk page. I will answer your questions as far as I can! Thank you again for contributing to Wikipedia. -- Andy W. ^{(talk/contrb.)} 19:32, 11 March 2007 (UTC)[reply]

CaCO3 Solubility

The calculated values in the table were already there when I edited the article. My contribution was to improve the accompanying text so that it better explained both the method for calculating the table and the trends of the table. The explanation for the solution being basic when CO₂ partial pressure is very low is given in the text. For the solution to come into equilibrium with extremely low ambient CO₂ pressures requires that nearly all the CO₂ escape from the solution and pass into the gas phase. This leaves the solution containing only Ca²⁺ and OH^–, which is, by its nature, very basic. The conditions given in the low end of the table are extremely difficult to produce in the lab. I can't think of a way of producing a partial CO₂ pressure of 10^–12 atm, because I don't know of any CO₂ scavenger that will produce so low a pressure. Karl Hahn (T) (C) 01:19, 10 May 2007 (UTC)[reply]