User:Wwoods/Relativistic rocket formulas
(A)------------------------------------------------------------------
Assuming a magical stardrive which allows you to accelerate continuously away from Earth at 10 m/s^2, the time taken to reach various distances is:
Earth dist : Earth time speed ship time ship distance __________ __________ ____________ _________ _____________ .05 ly : 0.31 yr 0.312 c 0.31 yr 0.048 ly .10 ly : 0.45 yr 0.426 c 0.43 yr 0.091 ly 0.25 ly : 0.73 yr 0.611 c 0.67 yr 0.198 ly 0.50 ly : 1.10 yr 0.755 c 0.94 yr 0.328 ly 1 ly : 1.70 yr 0.873 c 1.28 yr 0.487 ly 2 ly : 2.79 yr 0.9467 c 1.71 yr 0.644 ly 4 ly : 4.86 yr 0.9814 c 2.22 yr 0.768 ly 10 ly : 10.91 yr 0.99623 c 2.98 yr 0.868 ly 25 ly : 25.93 yr 0.99933 c 3.80 yr 0.915 ly 50 ly : 50.94 yr 0.999826 c 4.44 yr 0.932 ly 100 ly : 100.95 yr 0.9999557 c 5.09 yr 0.941 ly 1000 ly : 1000.95 yr 0.99999955 c 7.27 yr 0.949 ly 10000 ly : 10000.95 yr 0.9999999955 c 9.46 yr 0.950 ly
(B)------------------------------------------------------------------
More generally, if a ship can accelerate continuously away from Earth, at constant acceleration a, as measured onboard the ship,
Values as measured by an observer in Earth's frame of reference:
T: Earth time (since the ship's launch) D: Earth distance (from Earth to the ship) A: Earth acceleration (of the ship)
Values as measured by an observer on the ship:
a: ship acceleration (of the ship) τ: ship time (proper time) (since the ship's launch) d: ship distance (from Earth to the ship) j: distance travelled by ship
M: mass of ship M0: initial mass ρ: mass ratio = M0/M βex: effective exhaust speed(/c)
Relativistic quantities:
- : velocity parameter
a theta(tau) = - tau : velocity parameter c
v a beta = - = Tanh{ theta } = Tanh{ - tau } c c
1 a gamma = __________________ = Cosh{ theta } = Cosh{ - tau } 2 c Sqrt{ 1 - beta }
Recurring constants:
8 c = 2.99792458 × 10 m/sec
7 7 15 year = 3.155693 × 10 sec ( ~ pi × 10 sec, ~ Sqrt{10 } sec )
15 lightyear = 9.460530 × 10 metres
2 2 for a = 10 m/sec = 1.052626 ly / yr ,
a -8 -1 -1 - = 3.33564095 × 10 sec = 1.052626 year c
2 c 15 - = 8.98755179 × 10 metres = 0.9500051 light-years a
(C)------------------------------------------------------------------
In the ship's frame of reference,
a -2(a/c)tau v(tau) = c Tanh{ - tau } ; v(tau) -> c ( 1 - e ) c
2 2 c a c (a/c)tau D(tau) = - ( Cosh{ - tau } - 1 ) ; D(tau) -> __ e a c 2a
c a c a tau(D) = - ArcCosh{ ___ D + 1 } ; tau(D) -> - Ln{ ___ D } a 2 a 2 c c
2 2 c a c -(a/c)tau d(tau) = - ( 1 - Sech{ - tau } ) ; d(tau) -> - ( 1 - 2 e ) a c a
2 2 c a c j(tau) = - Ln{ Cosh[ - tau ] } ; j(tau) -> c × tau - - Ln{2} a c a
c a c (a/c)tau T(tau) = - Sinh{ - tau } ; T(tau) -> __ e a c 2a
(D)------------------------------------------------------------------
Alternately, in the Earth's frame of reference, your acceleration is measured as:
a A = ________ 3 gamma
2 3/2 A(v) = a ( 1 - (v/c) )
2 c a 2 D(T) = - ( Sqrt{ 1 + ( - T ) } - 1 ) a c
c a 2 T(D) = - Sqrt{ ( ___ D + 1 ) - 1 } a 2 c
aT c v(T) = ______________________ = ________________________ a 2 a -2 Sqrt{ 1 + ( - T ) } Sqrt{ 1 + ( - T ) } c c
v(T) 1 1 beta(T) = ____ = _____________________ = ______________________ c c 2 a -2 1/2 Sqrt{ 1 + ( ___ ) } { 1 + ( - T ) } aT c
a 2 gamma(T) = Sqrt{ 1 + ( - T ) } c
c a a 2 tau(T) = - Ln{ - T + Sqrt[ 1 + ( - T ) ] } a c c
a a A(T) = _______________________ = _____________________ a 2 3 a 2 3/2 Sqrt{ 1 + ( - T ) } { 1 + ( - T ) } c c
(E)------------------------------------------------------------------
For a trip which goes from standing start to standing finish, calculate the T, τ, etc. to reach the midpoint, then double.
- Voyage length
2c a 2 Voyage length = 2 T( D/2 ) = __ Sqrt{ ( ____ D + 1 ) - 1 } (Earth time) a 2 2c = Sqrt{ D^2 / c^2 + 4 D / a } 2 D 4 D = Sqrt{ ____ + _____ } 2 a c
Voyage length
2c a Voyage length = 2 tau( D/2 ) = __ ArcCosh{ ____ D + 1 } (ship time) a 2 2c =? ( 2 c / a ) ArcSinh{ 2 T(D/2) a / 2 / c }
a -2 Vmax = V( T(D/2) ) = c Sqrt{ 1 - ( ____ D + 1 ) } 2 or 2c
a Vmax = V( tau(D/2) ) = c Tanh{ ArcCosh( ____ D + 1 ) } 2 2c
- Voyage length
2 2c a Voyage length = 2 j( tau(D/2) ) = __ Ln{ ____ D + 1 } (ship's odometer) a 2 2c 2 for instance, for a = 1 kgal ( = 1000 cm/sec ~ 1 "gee" )
15 Distance to Alpha Cen = 4.3 ly = 41 Pm = 41 × 10 m 6 Tau to Alpha Cen = 111 × 10 sec = 3.5 yr
6 Time to Alpha Cen = 187 × 10 sec = 5.9 yr
V_max = 0.95 c
distance travelled = 2.3 ly
(F)------------------------------------------------------------------
For a perfectly efficient photon rocket,
- so
Mo a theta = ArcTanh{ beta } = Ln{ __ } = - tau, so M c
-(a/c)tau M(tau) = Mo e
For a perfectly efficient photon rocket, accelerating from v = 0 to β(×c),
Mo 1 + beta rho = __ = gamma ( 1 + beta ) = Sqrt{ __________ } M 1 - beta
or alternately,
2 rho - 1 beta(rho) = __________ 2 rho + 1
1 1 rho gamma(rho) = - ( rho + ___ ) ; gamma(rho) -> ___ 2 rho 2
For an imperfect rocket, with effective exhaust speed(/c) of βex,
- , so
-(a tau)/(c B_ex) theta = B_ex Ln { rho } , so M(tau) = Mo e
- , or
2B_ex rho - 1 1 + beta 1/2/B_ex beta(rho) = ____________ , or rho(beta) = { _________ } 2B_ex 1 - beta rho + 1
B_ex 1 B_ex -B_ex rho gamma(rho) = - ( rho + rho ) ; gamma(rho) -> _____ 2 2
(G)------------------------------------------------------------------
FAQ page for The Relativistic Rocket: http://math.ucr.edu/home/baez/physics/Relativity/SR/rocket.html also http://math.ucr.edu/home/baez/physics/Relativity/SR/acceleration.html http://math.ucr.edu/home/baez/physics/Relativity/SR/velocity.html
John Walker's relativity-exploring ship: http://www.fourmilab.ch/cship/cship.html
The Oh-My-God Particle: http://www.fourmilab.ch/documents/ohmygodpart.html
Erik Max Francis's frontpage: http://www.alcyone.com/max/noframes.html
Wayne Throop's frontpage: http://www.sheol.com/throopw
Chris Hillman's relativity page: http://www.math.washington.edu/~hillman/relativity.html
Jason Hinson's FAQ site: http://www.physics.purdue.edu/~hinson/ftl/index.html