User:Wikiscient/Sandbox

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Sigs

WikiDao ☯

ॐ WikiDao ☯ 22:46, 7 January 2011 (UTC)

WikiDao ☯ (talk) 18:18, 31 December 2010 (UTC)

WikiDao ☯ 18:48, 31 December 2010 (UTC)

Issue at WP:UAA

[1]→[2]→[3]

WikiDao (talk · contribs · deleted contribs · blacklist hits · AbuseLog · what links to user page · count · COIBot · Spamcheck · user page logs · x-wiki · status · Edit filter search · Google · StopForumSpam)
- Please check outrageous behavior at my talk page, especially bottom-most message. The large link leads to this terrifying page: [4]. Please let me know what I should do. Taisha24 (talk) 04:06, 6 January 2011 (UTC)

Statement by WikiDao:

{raises eyebrow}

This is not a complaint about a username violation, but I'll let a sysop move this thread somewhere else if that seems best.

User:Taisha24 has been informed several times that refactoring others' comments is not permitted per WP:TPOC (both at User talk:Taisha24 [5][6] and at the talk page where the refactoring occurred, Talk:Ganas [7][8][9][10][11]). Still Taisha24 persisted in this behavior[12] with an edit summary reading "minor edits, still playing with formatting". At that point, after issuing a Level 3 WP:TW warning[13], and since this editor seemed to be making "test edits", I created a User Sandbox in his/her userspace[14] and invited him/her to feel free to edit my text there as desired[15]. I deliberately included many spelling/grammar/etc mistakes in that text for Taisha24 to "correct" since that is what s/he seemed to want to experiment with doing. Part of that text was in Spanish and made use of the phrase wikt:tener ganas only because the talk page where the disruptive refactoring had occurred was of an article the name of which is derived (I think) from the Spanish word "ganas". In fact I used the example given at wiktionary: "Tengo ganas de bailar" and, because it was just sandbox-nonsense, I wrote (in Spanish) "I would like to dance in your sandbox". I then asked (in Spanish and the color orange) "And you, Taisha? What would you like to do?"

I am not sure what might seem "terrifying" or "outrageous" about any of that, but I apologize for having confused this editor if that is for whatever reason the effect these actions on my part had. I would be happy to take further action to remedy this problem and would welcome any suggestions as to what that might be.

WikiDao ☯ 04:57, 6 January 2011 (UTC)

I agree, this is not the right place for this report (and I as well will leave it to a sysop to move it), ~~WP:ANI~~WP:WQA would have been a better place. Anyway, as an uninvolved editor, WikiDao was completely in the right. Taisha24 might find some use in being adopted by an editor to become more familiar with the policies here, though. Anyway, with this I hope this can just be removed from here and discussed on the user's talk pages. d m z 12:27 am, Yesterday (UTC−5)

Section

I would look at it in terms of "kinetic energy transfer" (though the "Force/area" issue and other points mentioned above are also relevant, I agree). So wouldn't the following reasoning be valid?

Because the momentum of the handgun must equal the momentum of the bullet, the energy transferred by the handgun to the hand is much less than the energy transferred by the bullet to the target.

Consider the M1911 pistol which weighs about 1100 grams and fires .45 caliber slugs which weigh say about 11 grams:

m_{slug}=11grams

m_{gun}=1100grams=100m_{slug}

and since

m_{gun}\mathbf {v} _{gun}=m_{slug}\mathbf {v} _{slug}

we also have

\mathbf {v} _{gun}={\frac {m_{slug}}{m_{gun}}}\mathbf {v} _{slug}={\frac {1}{100}}\mathbf {v} _{slug}

The kinetic energy of the slug is

E_{slug}={\tfrac {1}{2}}m_{slug}v_{slug}^{2}

and that of the gun is then

E_{gun}={\tfrac {1}{2}}m_{gun}v_{gun}^{2}={\tfrac {1}{2}}100m_{slug}({\frac {1}{100}}\mathbf {v} _{slug})^{2}={\frac {1}{100}}({\tfrac {1}{2}}m_{slug}v_{slug}^{2})={\frac {1}{100}}E_{slug}

So, in this example, the kinetic energy of the handgun is only one-hundredth that of the slug. The kinetic energy absorbed by your hand is therefore far less than the kinetic energy absorbed by, say, a human body-part, which is why there is less tissue damage to your hand than there is to your target. WikiDao ☯ 00:40, 21 February 2011 (UTC)

Earth radius: mean radius 6371 km Angular velocity: $\mathrm {v} _{\perp }=r\,{\frac {d\phi }{dt}}$ and $\mathrm {v} _{\perp }=|\mathrm {\mathbf {v} } |\,\sin(\theta ).$

${\frac {d\phi }{dt}}={\frac {\mathrm {v} _{\perp }}{R}}={\frac {0.465km/s}{6371km}}=7.29*10^{-5}rad/s$

$r=R\,\cos(Latitude)=6371km*\cos(39^{\circ })=4951km$

$\mathrm {v} _{\perp 39^{\circ }}=4951km*(7.29*10^{-5}rad/s)\approx 361m/s$ (to the west)

${\frac {\mathrm {v} _{\perp 39^{\circ }}}{\mathrm {v} _{\perp 0^{\circ }}}}={\frac {r\,\omega }{R\,\omega }}={\frac {r}{R}}$

$\mathrm {v} _{\perp 39^{\circ }}=\mathrm {v} _{\perp 0^{\circ }}\,{\frac {r}{R}}=465m/s*\cos(39^{\circ })\approx 361m/s$

Perhaps it might make sense to consider this question in terms of Pressure, which is Force per unit area. The force of the handgun against your hand is the same as the force of the bullet striking the target, but that force is distributed over a much smaller area by the bullet than by the handgun.

Imagine holding a nail with the pointy end against the palm of your hand and hitting the nail with a hammer. Goes right through your hand and does a lot of painful damage, right? Now imagine holding a billiard ball in your hand and striking it with the exact same force with the same hammer. You'll feel that, sure, but it's not going to do anything like the same damage to your hand as in the case of the nail.

again, it's the same thing as if you were to hold a handgun in one hand and shoot yourself in the palm of your other hand. The hand with the gun is okay because the force has been distributed over the entire palm of your hand, whereas the hand

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Title	Author	Year	Country
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Random Koans

From Wikisource:The Gateless Gate (get another)

7. Joshu Washes the Bowl

A monk told Joshu: "I have just entered the monastery. Please teach me."

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