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User:Tet-Math/sandbox

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$K={\frac {\ a^{2}+b^{2}+c^{2}}{2}}$

$x={\sqrt {K-c^{2}\ }}\ \ \ \ \ \ \ \ y={\sqrt {K-b^{2}\ }}\ \ \ \ \ \ \ \ z={\sqrt {K-a^{2}\ }}$

$K=x^{2}+y^{2}+z^{2}$

$c={\sqrt {K-x^{2}\ }}\ \ \ \ \ \ \ \ b={\sqrt {K-y^{2}\ }}\ \ \ \ \ \ \ \ a={\sqrt {K-z^{2}\ }}$

$K=a^{2}+z^{2}\ \ \ \ \ \ \ \ K=b^{2}+y^{2}\ \ \ \ \ \ \ \ K=c^{2}+x^{2}$

$K={\biggl (}{\frac {\ a^{2}+b^{2}+c^{2}}{2}}{\biggr )}={\Bigl (}x^{2}+y^{2}+z^{2}{\Bigr )}={\Bigl (}a^{2}+z^{2}{\Bigr )}={\Bigl (}b^{2}+y^{2}{\Bigr )}={\Bigl (}c^{2}+x^{2}{\Bigr )}$

$c={\sqrt {K-x^{2}\ }}\ \ \ \ \ \ \ \ b={\sqrt {K-y^{2}\ }}\ \ \ \ \ \ \ \ a={\sqrt {K-z^{2}\ }}$

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