User:Mr splosh

hello world!

• Team B faced 47.2 overs, so their runrate is ${\frac {267}{47{\tfrac {1}{3}}}}={\frac {267}{\tfrac {142}{3}}}={\frac {801}{142}}\approx 5.64$
• Assuming that Team A and Team B had previously played as in the game in scenario one, the new net run rate for team A would be ${\frac {287+265}{50+50}}-{\frac {243+267}{50+47{\tfrac {1}{3}}}}={\frac {552}{100}}-{\frac {510}{97{\tfrac {1}{3}}}}\approx 0.28$