Math Formulae
http://en.wikipedia.org/wiki/Wikipedia:LATEX
[ ∫ − N N e x d x ] {\displaystyle {\Bigg [}\int _{-N}^{N}e^{x}\,dx{\Bigg ]}}
lim n → ∞ x n {\displaystyle \lim _{n\to \infty }x_{n}}
[ ∑ n = 0 ∞ x 2 ] {\displaystyle {\Bigg [}\sum _{n=0}^{\infty }x^{2}{\Bigg ]}}
( ( ( ( . . . ] ] ] ] {\displaystyle {\big (}{\Big (}{\bigg (}{\Bigg (}...{\Bigg ]}{\bigg ]}{\Big ]}{\big ]}}
x = − b ± b 2 − 4 a c 2 a {\displaystyle x={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}}
[ ∑ n = 0 ∞ x n n ! ] {\displaystyle {\Bigg [}\sum _{n=0}^{\infty }{\frac {x^{n}}{n!}}{\Bigg ]}}
⇒ 0 = δ S e f f B δ Δ ( k → ) = ∑ k → ′ V ( k → , k → ′ ) Δ ( k → ′ ) + 2 Δ ( k → ) 2 E k tanh ( E k 2 T ) {\displaystyle \Rightarrow 0={\frac {\delta S_{eff}^{B}}{\delta \Delta ({\vec {k}})}}=\sum _{{\vec {k}}'}V({\vec {k}},{\vec {k}}')\Delta ({\vec {k}}')+2{\frac {\Delta ({\vec {k}})}{2E_{k}}}\tanh \left({\frac {E_{k}}{2T}}\right)}
x 2 − x + 1 ) x 4 − 3 x 3 + 0 x 2 + 2 x − 5 ¯ {\displaystyle x^{2}-x+1\;{\overline {{\big )}x^{4}-3x^{3}+0x^{2}+2x-5}}}
S B H = c 3 A 4 ℏ G {\displaystyle S_{BH}={\frac {c^{3}A}{4\hbar G}}}
ℏ {\displaystyle \hbar }
y = − 1 x 2 + z 2 {\displaystyle y={\frac {-1}{x^{2}+z^{2}}}}
y = 6 1 + e − ( 5.085 − 0.1156 x ) {\displaystyle y={\frac {6}{1+e^{-(5.085-0.1156x)}}}}
T = r 2 + ( r − 1 ) ∇ + ( r − 3 ) ∇ − ( r − 4 , 6 , 8 , . . . ) Δ {\displaystyle T=r^{2}+(r-1)^{\nabla }+(r-3)^{\nabla }-(r-4,6,8,...)^{\Delta }}
n Δ = ∑ k = 1 n k {\displaystyle n^{\Delta }=\sum _{k=1}^{n}k}
n ∇ = ∑ k = 1 n k ( k + 1 ) 2 {\displaystyle n^{\nabla }=\sum _{k=1}^{n}{\frac {k(k+1)}{2}}}