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Fix incorrect information in Seasonal Energy Efficiency Rating

Typical SEER for residential central cooling units = 0.875 X EER
SEER is always a lower value than EER for the same equipment. This applies to unitary residential equipment. Certain types of equipment, for instance water-source heat pumps, are rated at different operating conditions and their EER ratings will not correlate to SEER of residential units.

http://ari.org/ARI/util/showdoc.aspx?doc=1028 ARI STANDARD 210/240-2008

pg89 4.1.1 SEER calculations for an air conditioner or heat pump having a single-speed compressor that was tested with a fixedspeed indoor fan installed, a constant-air-volume-rate indoor fan installed, or with no indoor fan installed. a. Evaluate the seasonal energy efficiency ratio, expressed in units of Btu/watt-hour, using: SEER = PLF(0.5) · EERB

pg90 where, the energy efficiency ratio determined from the B Test described in sections 3.2.1, 3.1.4.1, and 3.3, Btu/h per watt. PLF (0.5) = 1 - 0.5 · CD c, the part-load performance factor evaluated at a cooling load factor of 0.5, dimensionless. b. Refer to section 3.3 regarding the definition and calculation of Q  c (82) and E  c (82). If the optional tests described in section 3.2.1 are not conducted, set the cooling mode cyclic degradation coefficient, CD c, to the default value specified in section 3.5.3. If these optional tests are conducted, set CD c to the lower of: 1. The value calculated as per section 3.5.3; or 2. The section 3.5.3 default value of 0.25.

pg73 3.5.3 Cooling-mode cyclic-degradation coefficient calculation. Use the two optional dry-coil tests to determine the cooling-mode cyclic-degradation coefficient, c D C . Append “(k=2)” to the coefficient if it corresponds to a two-capacity unit cycling at high capacity. If the two optional tests are conducted but yield a tested c D C that exceeds the default c D C or if the two optional tests are not conducted, assign c D C the default value of 0.25. The default value for two-capacity units cycling at high capacity, however, is the low-capacity coefficient, i.e., ) ( 2 k Cc D = c D C . Evaluate c D C using the above results and those from the section 3.4 dry-coil steady-state test.