Tsankov Island

Tsankov Island

Tsankov Island Location of Tsankov Island Tsankov Island Tsankov Island (Antarctic Peninsula)
Geography
Location	Antarctica
Coordinates	65°03′58″S 64°08′38″W
Archipelago	Wilhelm Archipelago
Area	9.48 ha (23.4 acres)
Length	625 m (2051 ft)
Width	216 m (709 ft)
Administration
Administered under the Antarctic Treaty System
Demographics
Population	uninhabited

Tsankov Island (Bulgarian: Цанков остров, romanized: Tsankov ostrov, IPA: [t͡sɐnˈkɔf ˈɔstrof]) is the mostly ice-covered island 625 m long in west-southwest to west-northeast direction and 216 m wide in the Dannebrog Islands group of Wilhelm Archipelago in the Antarctic Peninsula region. Its surface area is 9.48 ha.

The feature is named after the dermatologist Nikolay Tsankov, participant in the 2010/11 and subsequent Bulgarian Antarctic campaigns.

Location

Tsankov Island is located at 65°03′58″S 64°08′38″W, which is 293 m northwest of Stego Island, 175 m east of Bodloperka Island, 1.18 km southeast of Sprey Island and 1.25 km west-southwest of Taralezh Island. British mapping in 2001.

Maps

• British Admiralty Nautical Chart 446 Anvers Island to Renaud Island. Scale 1:150000. Admiralty, UK Hydrographic Office, 2001
• Brabant Island to Argentine Islands. Scale 1:250000 topographic map. British Antarctic Survey, 2008
• Antarctic Digital Database (ADD). Scale 1:250000 topographic map of Antarctica. Scientific Committee on Antarctic Research (SCAR). Since 1993, regularly upgraded and updated

See also

• List of Antarctic and subantarctic islands

References

• Tsankov Island. SCAR Composite Gazetteer of Antarctica
• Bulgarian Antarctic Gazetteer. Antarctic Place-names Commission. (details in Bulgarian, basic data in English)

External links

• Tsankov Island. Adjusted Copernix satellite image

This article includes information from the Antarctic Place-names Commission of Bulgaria which is used with permission.