Talk:Truncated octahedron

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Polyhedra

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The following references may be useful when improving this article in the future:

* Viana, Vera; Xavier, João Pedro; Aires, Ana Paula; Campos, Helena (2019). "Interactive Expansion of Achiral Polyhedra". In Cocchiarella, Luigi (ed.). ICGG 2018 - Proceedings of the 18th International Conference on Geometry and Graphics: 40th Anniversary - Milan, Italy, August 3-7, 2018. p. 1121. doi:10.1007/978-3-319-95588-9. ISBN 978-3-319-95588-9.

I'm too primitive to get it

The truncated octahedron is the only tridimensional primitive parallelohedra.

(I'll correct that to –hedron.) Does tridimensional here mean 'in 3space' or something else? What does primitive mean? —Tamfang (talk) 05:56, 21 January 2011 (UTC)[reply]

Definitely means 3-space. I found primary parallelohedron [1]. Tom Ruen (talk) 18:19, 21 January 2011 (UTC)[reply]

suggestion: dotted lines for invisible edges?!

may I suggest to use dotted lines for the invisible edges in the drawings of the projections? not using them leads to puzzling effects: so e.g. in the column "edge 4-6" ot the table of "orthogonal projections" you think to see pentagons as surface-polygons (in the first row...) thanx! --HilmarHansWerner (talk) 06:18, 2 January 2017 (UTC)[reply]

Additional information

compared to similar articles (eg Octahedron) there is some missing basic information about dimensions...

where side length = a

Circumsphere (vertex) radius = 0.5 * sqrt(10) * a ~= 1.5811a

Midsphere (mid-edge) radius = 1.5 * a == 1.5a

Insphere(1) (square face) radius = sqrt(2) * a ~= 1.4142a

Insphere(2) (hexagonal face) radius = 0.5 * sqrt(6) * a ~= 1.2247a

Volume = (1/3) * sqrt(2) * (3a)^3 - sqrt(2) * a^3

also it only requires 6 (not 12) rectangles, of sides [a, 3a] with the short edges along where octagons meet, passing through the center, each corner mapping a vertex.

I'd edit them in, but templates and formatting aren't my forte, so any help is appreciated
74.214.226.120 (talk) 17:39, 19 January 2017 (UTC)[reply]