Talk:Total dynamic head

	Physics portal This article is within the scope of WikiProject Physics, a collaborative effort to improve the coverage of Physics on Wikipedia. If you would like to participate, please visit the project page, where you can join the discussion and see a list of open tasks.PhysicsWikipedia:WikiProject PhysicsTemplate:WikiProject Physicsphysics articles
Low	This article has been rated as Low-importance on the project's importance scale.
	This article is supported by Fluid Dynamics Taskforce.

Should not the velocity head be included in the total dynamic head?

The fluid still needs to be moving at its final destination, so there should also be a term indicating kinetic energy (i.e (v^2)/2*g). Is this not correct? —Preceding unsigned comment added by 75.93.162.59 (talk) 01:32, 1 April 2010 (UTC)[reply]

I have the same question. I think the answer is that the kinetic term, in practical applications, is typically small compared to the other terms so it is often ignored. But it should be there. --Baller McGee (talk) 13:08, 10 August 2021 (UTC)[reply]

Things are wrong

I'm a plumbing engineer and I know some things are wrong, but I don't have time to find good sources etc, so I'm just posting this here:

"This equation can be derived from Bernoulli's Equation." Not true. Bernoulli doesn't consider friction loss. You could change to Navier-Stokes Equation and it would be accurate.

"For incompressible liquids such as water, Static lift + Pressure head together equal the difference in fluid surface elevation between the suction basin and the discharge basin." Not true if there is a source of pressure other than gravity in one of the basins. Also not sure why we're talking about basins. This equation should be applicable to many things that are not basins. Like from a pump to a nozzle or tool, and in real life tools usually have pressure requirements to do what they're meant to do. — Preceding unsigned comment added by 12.138.194.66 (talk) 02:39, 7 December 2023 (UTC)[reply]