Talk:Root-mean-square speed

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how does the units work out?

the units are:

v²(Distance²/Time²)=3*R(Energy/(mole*Temprature))*Temprature/Moleculare weight(mass/mole)

Energy=mass*Distance/Time²

Therefore:
v²(Distance²/Time²)=3*R(~~mass~~*Distance/Time²/(~~mole~~*~~Temprature~~))*~~Temprature~~/Moleculare weight(~~mass~~/~~mole~~)

I am missing a duplication in the Distance...

Can someone help me? —Preceding unsigned comment added by 85.250.175.153 (talk) 21:35, 7 December 2008 (UTC)[reply]

You missed out one distance in the energy definition. Remember: E = mc², so in SI, 1 Joule is 1 kg m² s^–2. So, kT/m has units of velocity squared. Grunkhead (talk) —Preceding undated comment added 12:33, 5 June 2009 (UTC).[reply]

Iteresting question: How can we incorperate the speed of light into these equations? This has to be the limiting value for the speed. -Anonymous If one wants to, say find the root mean square speed of particles inside of a star the speeds would probably approach very high values, which becomes an issue. — Preceding unsigned comment added by 68.73.192.73 (talk) 20:44, 3 January 2013 (UTC)[reply]