Talk:Powerball (Australia)

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The link to the Missouri gambling site is now out of date and needs to be updated.
Japan section reads as though it was written by the gambling industry - quotes of 160% returns are 'citation needed'.

The US Powerball game, I believe, was invented so that players could win by matching only ONE number (the PowerBALL). The US games Mega Millions and Hot Lotto, as well as others, allow this. Yet, the Australian lotteries did not have that in mind when it was brought across the Pacific. You need THREE numbers (2+1 or 3+0) to win Down Under. 216.179.123.146 17:44, 15 September 2007 (UTC)[reply]

Fair use rationale for Image:Logo s powerball.gif

Image:Logo s powerball.gif is being used on this article. I notice the image page specifies that the image is being used under fair use but there is no explanation or rationale as to why its use in this Wikipedia article constitutes fair use. In addition to the boilerplate fair use template, you must also write out on the image description page a specific explanation or rationale for why using this image in each article is consistent with fair use.

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BetacommandBot (talk) 12:30, 8 March 2008 (UTC)[reply]

"Odds based on 12 games"

Simply put: why? 12 games seems like such a strange number and there's nothing else in the article to suggest that playing 12 games has some significance. Also bear in mind that you cannot just divide the 76,767,600 in 76,767,600:1 and call that the odds of winning once in 12 games; the Binomial Distribution strongly disagrees with that. I'd suggest that this article uses only a single table which merges all the information (and getting rid of this "12" business.) I'll give it some time before making the changes just in case somebody points out all the sense I've missed! JaeDyWolf ~ Baka-San (talk) 16:46, 7 May 2013 (UTC)[reply]

Problem with Odds?

I am trying to calculate the odds for a "Powerhit" game (20 games including all PowerBall numbers 1...20). This would reduce PowerBall to a 7 out of 35 lotto game. Applying (N over K) = 35!/K!/(35-K)! with K=7...2 I am getting odds of 6,724,520 | 1,623,160 | 324,632 | 52,360 | 6,545 | 595 respectively. This seems to be at "Odds" with the table! It would be great to include the odds for this popular game as it greatly reduces the odds. — Preceding unsigned comment added by Drquark (talk • contribs) 05:20, 19 January 2019 (UTC)[reply]